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Haryana PMT Haryana PMT Solved Paper-2006

  • question_answer
    The magnetic force on a point charge is                                                 \[\overrightarrow{\mathbf{F}}\text{=q(}\overrightarrow{\mathbf{V}}\text{ }\!\!\times\!\!\text{ }\overrightarrow{\mathbf{B}}\text{)}\]                 Here,        \[q\] = electric charge                                                  \[\overrightarrow{\mathbf{V}}\]= velocity of point charge                                                 \[\overrightarrow{\mathbf{B}}\] = magnetic Held                 The dimension of \[\overrightarrow{\mathbf{B}}\] is :

    A)                  \[[ML{{T}^{-1}}A]\]                       

    B)  \[[{{M}^{2}}L{{T}^{2}}{{A}^{-1}}]\]

    C)                  \[[M{{T}^{-2}}{{A}^{-1}}]\]                        

    D)  none of these

    Correct Answer: C

    Solution :

                    \[F=q\overrightarrow{v}\times \overrightarrow{B}\] or           \[F=\,q\,\,v\,\,B\,\,\sin \theta \]                 \[[B]=\left[ \frac{F}{qv} \right]=\frac{[ML{{T}^{-1}}]}{[AT][L{{T}^{-1}}]}\]                 \[=[M{{T}^{-2}}{{A}^{-1}}]\]


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