A) \[65%\]
B) \[100%\]
C) \[6.5%\]
D) zero
Correct Answer: C
Solution :
\[CaC{{O}_{3}}(s)\xrightarrow{{}}CaO(s)+C{{O}_{2}}(g)\] \[{{K}_{p}}={{P}_{C{{O}_{2}}}}\] (only gaseous molecule count) \[{{K}_{p}}={{K}_{c}}{{(RT)}^{\Delta n}}\] \[\Rightarrow \] \[1.16=\frac{x}{5}{{(0.0821\times 1073)}^{1}}\] \[x=\frac{1.16\times 5}{0.0821\times 1073}=\frac{5.8}{88.1}=0.0658\] \[=0.0658\times 100=6.58%\]You need to login to perform this action.
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