A) \[70\text{ }N/{{m}^{2}}\]
B) \[140\text{ }N/{{m}^{2}}\]
C) \[280\text{ }N/{{m}^{2}}\]
D) zero
Correct Answer: C
Solution :
The excess pressure p is given by \[P=\frac{4T}{R}\]where T is surface tension and R is radius of bubble. Given, \[t=70\times {{10}^{-3}}N/m,\,\,R=1mm={{10}^{-3}}m\] \[\therefore \] \[p=\frac{4\times 70\times {{10}^{-3}}}{{{10}^{-3}}}=280N/{{m}^{2}}\]You need to login to perform this action.
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