A) \[1\]
B) \[2\]
C) \[3\]
D) \[0\]
Correct Answer: A
Solution :
Number of nodal planes \[=l\] For \[{{p}_{x}}\]orbital, \[l=1\] \[\therefore \] Number of nodal planes = 1 (c) (d) Electronegativity \[\propto \frac{1}{nucleophilicity}\] \[\therefore \] \[CH_{3}^{-}\] has the highest nucleophilicity.You need to login to perform this action.
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