A) \[\text{10 }\!\!\mu\!\!\text{ V}\]
B) \[\text{40 }\!\!\mu\!\!\text{ V}\]
C) \[\text{10mV}\]
D) \[\text{10mV}\]
Correct Answer: B
Solution :
By Faradays second law, induced emf \[e=-\frac{Nd\phi }{dt}\] which gives \[e=-L\frac{dI}{dt}\] \[\therefore \] \[|e|=2\times {{10}^{-3}}\times 20\times {{10}^{-3}}V=40\mu V\]You need to login to perform this action.
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