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Haryana PMT Haryana PMT Solved Paper-2010

  • question_answer
    Two masses of 10 kg and 20 kg respectively are connected by a massless spring as shown in figure. A force of 200 N acts on the 20 kg mass. A: the instant shown, the 10 kg mass has acceleration \[12\text{ }m/{{s}^{2}}.\] What is the acceleration of 20 kg mass?

    A)  \[12m/{{s}^{2}}\]                           

    B) \[~4m/{{s}^{2}}\]

    C)  \[10m/{{s}^{2}}\]                           

    D)  Zero

    Correct Answer: B

    Solution :

                    As the mass of 10 kg has acceleration\[12\text{ }m/{{s}^{2}}\], therefore it applies \[120N\]force on mass \[20kg\] in a backward direction. \[\therefore \] Net forward force on \[20kg\]mass                 \[=200-120=80N\] \[\therefore \]Acceleration \[=\frac{80}{20}=4m/{{s}^{2}}\]


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