A) 2L
B) L
C) 4L
D) \[\frac{L}{2.}\]
Correct Answer: A
Solution :
As \[L\propto {{N}^{2}}r\] \[\frac{{{L}_{1}}}{{{L}_{2}}}={{\left[ \frac{{{N}_{1}}}{{{N}_{2}}} \right]}^{2}}\times \frac{{{r}_{1}}}{{{r}_{2}}}\] \[\Rightarrow \] \[\frac{L}{{{L}_{2}}}={{\left[ \frac{1}{2} \right]}^{2}}\times \left[ \frac{r}{r/2} \right]=\frac{1}{2}\] \[{{L}_{12}}=2L\]You need to login to perform this action.
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