A) \[4.89\]
B) \[3.89\]
C) \[2.20\]
D) None of these
Correct Answer: A
Solution :
Given, \[[{{H}_{3}}{{O}^{+}}]=1.3\times {{10}^{-5}}\] \[\because \] \[pH=-\log [{{H}_{3}}{{O}^{+}}]\] \[=-\log (1.3\times {{10}^{-5}})\] \[=-(\log 1.3+\log {{10}^{-5}})\] \[=-0.1139+5\] \[\therefore \] \[pH=4.886\approx 4.89\]You need to login to perform this action.
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