A) \[0.266\]
B) \[0.366\]
C) \[2.66\]
D) \[3.66\]
Correct Answer: A
Solution :
\[\underset{0}{\mathop{PC{{l}_{5}}}}\,\underset{0}{\mathop{PC{{l}_{3}}}}\,+\underset{0}{\mathop{C{{l}_{2}}}}\,\underset{initilly}{\mathop{{}}}\,\] \[\frac{2\times 60}{100}\] \[\frac{2\times 40}{100}\] \[\frac{2\times 40}{100}\] at equilibrium Volume of container \[=2L\] \[{{K}_{c}}=\frac{\left( \frac{2\times 40}{100\times 2} \right)\left( \frac{2\times 40}{100\times 2} \right)}{\frac{2\times 60}{100\times 2}}\] \[=0.266\]You need to login to perform this action.
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