Haryana PMT Haryana PMT Solved Paper-2011

  • question_answer
    A ray of light is incident on the surface of a medium with the velocity of light at angle of \[45{}^\circ \] and refracted in medium at an angle of \[30{}^\circ \]. What will be the velocity of light in the medium?

    A)                  \[1.96\times {{10}^{8}}m/s\]    

    B)  \[2.12\times {{10}^{8}}m/s\]

    C)                  \[3.18\times {{10}^{8}}m/s\]    

    D)  \[3.33\times {{10}^{8}}m/s\]

    Correct Answer: B

    Solution :

                    \[\mu =\frac{\sin \,i}{\sin \,r}=\frac{{{v}_{a}}}{{{v}_{m}}}\]                 or            \[\frac{\sin \,{{45}^{0}}}{\sin \,{{30}^{0}}}=\frac{3\times {{10}^{8}}}{{{v}_{m}}}\]                 \[\therefore \]\[{{v}_{m}}=3\times {{10}^{8}}\times \frac{1/2}{1/\sqrt{2}}\]                         \[=3\times {{10}^{8}}\times \frac{1}{\sqrt{2}}\]                         \[=2.12\times {{10}^{8}}m/s\]


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