A) \[0.04\text{ }M\]
B) \[0.8M\]
C) \[0.4M\]
D) \[0.08M\]
Correct Answer: B
Solution :
\[0.2\,mol\,HCl=0.2\,mol\,C{{l}^{-}}ion\] \[0.1mol\,CaC{{l}_{2}}=0.2\,mol\,C{{l}^{-}}ion\] Total \[C{{l}^{-}}\] ion \[=0.4\text{ }mol\] Hence, molarity of \[C{{l}^{-}}\] ion \[=\frac{0.4}{500}\times 1000\]\[=0.8M\]You need to login to perform this action.
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