A) \[0{}^\circ \]
B) \[180{}^\circ \]
C) \[90{}^\circ \]
D) \[45{}^\circ \]
Correct Answer: C
Solution :
Here, p = i2 cost +j2 cost t \[F\frac{dp}{dt}=-2i\sin t+2j\]cos t \[F.P=(-2i\sin t+2j\cos t).(2i\cos t+j\sin t)\] \[=-4\sin t\cos t=+\,4\sin t\cos t=0\] Therefore, \[\theta ={{90}^{0}}\]You need to login to perform this action.
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