A) 1.66Wb
B) 1.66 N Wb
C) 1.66 m Wb
D) 1.66 \[\mu \] Wb
Correct Answer: C
Solution :
\[\theta ={{\mu }_{r}}{{\mu }_{0}}\frac{{{N}^{2}}}{l}Ai\] \[=\frac{600\times 4\pi \times {{10}^{7}}\times 50\times \pi {{(7.5\times {{10}^{-3}})}^{2}}\times 3}{6\times {{10}^{10-1}}}\] \[=1.66\times {{10}^{-3}}Wb\] \[=1.66mWb\]You need to login to perform this action.
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