A) \[~{{F}_{2}}<C{{l}_{2}}<{{I}_{2}}>B{{r}_{2}}\]
B) \[~{{F}_{2}}<B{{r}_{2}}<C{{l}_{2}}<{{I}_{2}}\]
C) \[~C{{l}_{2}}<B{{r}_{2}}<{{F}_{2}}<{{I}_{2}}\]
D) \[{{I}_{2}}<B{{r}_{2}}<C{{l}_{2}}<{{F}_{2}}\]
Correct Answer: D
Solution :
Halogens are strong oxidising agents. The oxidising power of halogen decreases from fluorine to iodine, because their reduction potential decreases from fluorine to iodine. The increasing order of their oxidising power is as: \[\begin{align} & \text{Element:}\,\,\,\,\,\,\,\,\,\,{{I}_{2}}\,\,\,\,\,\,\,\,\,\,\,\,<\,\,\,\,\,B{{r}_{2}}\,\,\,\,\,\,\,<\,\,\,\,C{{l}_{2}}\,\,\,\,\,\,\,<\,\,\,\,\,{{F}_{2}} \\ & \text{Reduction}\,\,+0.54\,\,\,\,\,\,\,\,\,+1.06\,\,\,\,\,\,\,\,+1.36\,\,\,\,\,\,\,+2.87 \\ & \text{potential:} \\ \end{align}\]
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