A) isobutane
B) isobutylene
C) sodium-t-butoxide
D) t-butylmethylether
Correct Answer: B
Solution :
\[\underset{t-\text{butylbromide}}{\mathop{C{{H}_{3}}-\underset{C{{H}_{3}}}{\overset{C{{H}_{3}}}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-Br}}\,+\underset{\begin{smallmatrix} \,\,\,\,\text{sodium} \\ \text{methoxide} \end{smallmatrix}}{\mathop{C{{H}_{3}}ONa}}\,\to \underset{\begin{smallmatrix} 2-\text{methyl}\,\text{propene} \\ \,\,\,\,\,\,\,\,\,(isobutylene) \end{smallmatrix}}{\mathop{C{{H}_{3}}-\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{C}}\,}}\,=C{{H}_{2}}}}\,\] \[\underset{\text{methanol}}{\mathop{+\,C{{H}_{3}}OH}}\,+NaBr\]
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