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J & K CET Engineering J and K - CET Engineering Solved Paper-2003

  • question_answer
    Three dice are thrown simultaneously, then probability of throwing a total greater than 4 is

    A)  \[1/54\]         

    B)  \[53/54\]

    C)  \[5/108\]        

    D)  None of these

    Correct Answer: B

    Solution :

    P(getting a sum greater than 4) \[=1-P\] (getting a sum less than 5)    ... (i) For sum 3, number of cases =1 For sum 4, number of cases =3 Total number of cases = 4 From Eq. (i), \[P=1-\frac{4}{216}=1-\frac{1}{54}=\frac{53}{54}\]


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