A) \[-4,1\]
B) \[4,-1\]
C) \[2,\,\,\,\sqrt{3}\]
D) \[-2,-\,\,\,\sqrt{3}\]
Correct Answer: A
Solution :
Since, one root of the equation \[{{x}^{2}}+px+q=0\] is \[2+\sqrt{3},\] then the other root will be \[2-\sqrt{3}\]. \[\therefore \] Sum of roots, \[2+\sqrt{3}+2-\sqrt{3}=-p\] \[\Rightarrow \] \[4=-p\] \[\Rightarrow \] \[p=-4\] and product of roots \[(2+\sqrt{3})(2-\sqrt{3})=q\] \[\Rightarrow \]\[1=q\] Hence, required values of p and q are \[-4\] and respectively.You need to login to perform this action.
You will be redirected in
3 sec