A) \[{{4}^{5/2}}\]
B) \[{{4}^{5}}\]
C) \[{{4}^{3}}\]
D) None of these
Correct Answer: B
Solution :
Let a and r be the first term and common ratio of a GP. \[\therefore \] \[{{T}_{3}}=4\] \[\Rightarrow \] \[a{{r}^{2}}=4\] ??(i) Now, \[a.\,a{{r}^{1}}.\,\,a{{r}^{2}}\,.\,a{{r}^{3}}\,.a{{r}^{4}}\] \[={{(a{{r}^{2}})}^{5}}={{(4)}^{5}}\] [from Eq. (i)]You need to login to perform this action.
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