A) \[1/54\]
B) \[53/54\]
C) \[5/108\]
D) None of these
Correct Answer: B
Solution :
P(getting a sum greater than 4) \[=1-P\] (getting a sum less than 5) ... (i) For sum 3, number of cases =1 For sum 4, number of cases =3 Total number of cases = 4 From Eq. (i), \[P=1-\frac{4}{216}=1-\frac{1}{54}=\frac{53}{54}\]You need to login to perform this action.
You will be redirected in
3 sec