A) \[R-\left( -\frac{b}{2a} \right)\]
B) \[R-(-\infty ,\,\,-1)\]
C) \[(-1,\infty )-\left\{ -\frac{b}{2a} \right\}\]
D) \[R-\left( \left\{ -\frac{b}{2a} \right\}\cap (-\infty ,-1) \right)\]
Correct Answer: C
Solution :
Given that, \[f(x)\log \{(a{{x}^{2}}+bx+c)\,\,(x+1)\}\,\] \[=\log (a{{x}^{2}}+bx+c)+\log (x+1)\] For \[f(x)\] to be defined \[a{{x}^{2}}+bx+c>0\] and \[x+1>0\] \[\Rightarrow \] \[x>-1\] Hence, option [c] is correct.You need to login to perform this action.
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