A) \[P(A)<P(\bar{B})\]
B) \[P(A)>P(\bar{B})\]
C) \[P(A)<P(B)\]
D) None of these
Correct Answer: A
Solution :
Since, A and B are mutually exclusive events. Then, \[P(A\cup B)=P(A)+P(B)\] \[\Rightarrow \] \[P(A)+P(B)\le 1\] \[\Rightarrow \] \[P(A)\le 1-P(B)\] or \[P(B)\le 1-P(A)\] \[\Rightarrow \] \[P(A)\le P(\overline{B})\] or \[P(B)\le P(\overline{A})\] Hence, option [a] is correct.You need to login to perform this action.
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