A) \[200\]
B) \[100\]
C) \[50\]
D) \[400\]
Correct Answer: B
Solution :
The average power consumed in an AC circuit is given by \[P=\frac{{{V}_{0}}{{I}_{0}}}{2}\cos \phi \] where \[\phi \] is phase angle and \[{{V}_{0}}\] and \[{{I}_{0}}\] the peak value of voltage and current. Given, \[{{V}_{0}}=200volt,\,\,\,\,\,\,{{I}_{0}}=2A,\,\,\,\,\,\,\phi =\frac{\pi }{3}.\] \[P=\frac{200\times 2}{2}\cos \frac{\pi }{3}\] \[=\frac{200\times 2}{2}\times \frac{1}{2}=100W\]
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