A) \[\sqrt{2n}\]
B) \[\frac{n}{\sqrt{2}}\]
C) \[2n\]
D) \[n\]
Correct Answer: D
Solution :
The period of oscillation of a body of mass m suspended by a spring (force constant k) is On cutting the spring in two equal parts, the length of each part will remain half and the force constant will be doubled (2 k). Therefore, \[T'=2\pi \sqrt{\frac{2m}{2k}}=T\] Since, time period remains same in both cases, frequency of oscillation is also same.You need to login to perform this action.
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