A) \[12\times {{10}^{-1}}\text{ }Nm\]
B) \[12\times {{10}^{-3}}\text{ }Nm\]
C) \[24\times {{10}^{-1}}Nm\]
D) \[24\times {{10}^{-3}}\text{ }Nm\]
Correct Answer: B
Solution :
Torque \[(\tau )\] on a dipole in an electric field (E) is given by \[\tau =pE\,\sin \theta \] where p is electric dipole moment. \[\therefore \] \[\tau =(q\times l)E\,\sin \theta \] Torque is maximum, when \[\theta ={{90}^{o}},\] \[\sin \,\,{{90}^{o}}=I\] \[\therefore \] \[\tau =qlE\] \[=2\times {{10}^{-6}}\times \frac{3}{100}\times 2\times {{10}^{5}}\] \[\tau =12\times {{10}^{-3}}Nm\]You need to login to perform this action.
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