A) 91.3%
B) 87%
C) 100%
D) 74%
Correct Answer: B
Solution :
\[Ba{{(N{{O}_{3}})}_{2}}B{{a}^{2+}}+2N{{O}_{3}}^{-}\] \[\begin{align} & \text{At}\,\text{t}\,\text{= 0}\,\,\,\,\,\,\,0.1\,M\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,0\,\,\,\,\,\,\,\,\,\,\,0 \\ & \text{At}\,\text{equ}\text{.}\,\,\,\,\,(0.1-x)M\,\,\,\,\,\,x\,M\,\,\,\,\,2x\,M \\ \end{align}\] \[i=\frac{(0.1-x)+x+2x}{0.1}\] \[2.74=\frac{0.1+2x}{0.1}\] \[2.74=\frac{0.1+2x}{0.1}\] \[0.1+2x=0.274\] \[2x=0.274-0.1=0.174\] \[x=\frac{0.174}{2}=0.087\] \[\therefore \]Degree of dissociation \[=\frac{0.087}{0.1}\times 100=87%\]You need to login to perform this action.
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