A) \[{{x}^{2}}+{{y}^{2}}-24x-y-25=0\]
B) \[{{x}^{2}}+{{y}^{2}}-30x-10y+225=0\]
C) \[{{x}^{2}}+{{y}^{2}}-16x-18y+64=0\]
D) \[{{x}^{2}}+{{y}^{2}}-20x-12y+144=0\]
Correct Answer: B
Solution :
Since, the perpendicular from centre to the circle is equal to the radius of the circle.You need to login to perform this action.
You will be redirected in
3 sec