J & K CET Engineering J and K - CET Engineering Solved Paper-2004

  • question_answer
    Two forces    \[{{\vec{F}}_{1}}=3\hat{i}-2\hat{j}+\hat{k}\]  and \[{{\vec{F}}_{2}}=\hat{i}-3\hat{j}+5\hat{k}\] acting on a particle at A, move to .6. The work done if the position vector of \[\vec{A}\] and \[\vec{B}\]are \[-2\hat{i}+5\hat{k}\]and \[-3\hat{i}-7\hat{j}+2\hat{k}\]is

    A)  \[25\]            

    B)  \[13\]

    C)  \[26\]           

    D)  \[28\]

    Correct Answer: B

    Solution :

    Given that,  \[{{\vec{F}}_{1}}=3\hat{i}-2\hat{j}+\hat{k}\]and \[{{\vec{F}}_{2}}=\hat{i}-3\hat{j}+5\hat{k}\]and \[\overrightarrow{OA}=-2\hat{i}+5\hat{k}\] and \[\overrightarrow{OB}=-3\hat{i}-7\hat{j}+2\hat{k}\] Total force \[\vec{F}={{\vec{F}}_{1}}+{{\vec{F}}_{2}}=4\hat{i}-5\hat{j}+6\hat{k}\] and displacement \[\vec{d}=\overrightarrow{OB}-\overrightarrow{OA}\] \[=-\hat{i}-7\hat{j}-3\hat{k}\] \[\therefore \] Work done \[=\vec{d}.\vec{F}\] \[=(-\hat{i}-7\hat{j}-3\hat{k}).(4\hat{i}-5\hat{j}+6\hat{k})\] \[=-4+35-18\] \[=13\]


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