A) \[3\pi {{a}^{2}}\] sq unit
B) \[2{{a}^{2}}\] sq unit
C) \[{{a}^{2}}\]sq unit
D) None of these
Correct Answer: A
Solution :
In an equilateral triangle length of median \[CD=\frac{\sqrt{3}}{2}a.\] Also, centroid of triangle lies on the centre of circle. \[\therefore \] \[OC=2\times \frac{\sqrt{3}}{2}a=\sqrt{3}a\] \[\therefore \] Area of circle =\[\pi {{(OC)}^{2}}\] \[=3\pi {{a}^{2}}\,\,sq\,\,unit\]You need to login to perform this action.
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