A) \[-(2+3i),\,(1)\]
B) \[(3+2i),(1)\]
C) \[(3+6i),(3)\]
D) None of these
Correct Answer: A
Solution :
Given equation of circle is \[z\,\bar{z}+(2+3i)\bar{z}-2(2-3i)z+12=0\] Here, centre is \[\{-(2+3i)\}\] and radius \[=\sqrt{|2+3i{{|}^{2}}-12}=\sqrt{13-12}=1\]
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