A) \[\frac{1}{2}\]
B) \[\frac{1}{5}\]
C) \[\frac{1}{10}\]
D) \[\frac{1}{20}\]
Correct Answer: C
Solution :
In a regular hexagon, there are two equilateral triangle are possible. \[\therefore \] Required probability \[=\frac{2}{^{6}{{C}_{3}}}\] \[\frac{2}{\frac{6\times 5\times 4}{3\times 2}}=\frac{1}{10}\]You need to login to perform this action.
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