A) \[4T\]
B) \[2T\]
C) \[T\]
D) \[r\]
Correct Answer: B
Solution :
The time period of vibration magnetometer is given by \[T=2\pi \sqrt{\frac{I}{MH}}\] where \[I\] is moment of inertia, M the magnetic moment and H the horizontal component of earth's magnetic field. Also, \[\text{I}=m{{r}^{2}}\] where m is mass and r the radius. When mass is increased four times. \[I'=4I\] \[\therefore \] \[T'=2\pi \sqrt{\frac{4I}{MH}}\] \[=2\times 2\pi \sqrt{\frac{I}{MH}}=2T\]You need to login to perform this action.
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