A) \[3\,cm\]
B) \[0.3\,cm\]
C) \[3\text{ }mm\]
D) \[~3\text{ }m\]
Correct Answer: A
Solution :
For no leakage, \[h\rho g=\frac{2T}{R}\] \[\Rightarrow \] \[T=\frac{Rh\rho g}{2}\] \[\Rightarrow \] \[h=\frac{2T}{R\rho g}\] Given, \[T=75\times {{10}^{-3}}N/m,\,\,g=10m/{{s}^{2}},\] \[R=0.5\times {{10}^{-3}}m\] \[h=\frac{2\times 75\times {{10}^{-3}}}{(0.5\times {{10}^{-3}})(1000)10}\] \[\Rightarrow \] \[h=30\times {{10}^{-3}}\times 100cm\] \[=3cm\]You need to login to perform this action.
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