A) 0.2 N
B) 0.4 N
C) 0.8 N
D) 0.6 N
Correct Answer: B
Solution :
Normality of the mixed solution \[=\frac{{{N}_{1}}{{V}_{1}}+{{N}_{2}}{{V}_{2}}}{{{V}_{1}}+{{V}_{2}}}\] \[=\frac{0.6\times \frac{100}{100}+0.3\times \frac{200}{1000}}{\frac{100+200}{1000}}\] \[=\frac{0.6\times 0.1\times 0.3\times 0.2}{0.3}\] \[=\frac{0.06+0.06}{0.3}=\frac{0.12}{0.3}=0.4\,N\]You need to login to perform this action.
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