A) \[CrO_{4}^{2-}\]
B) \[Cr(OH)_{3}^{-}\]
C) \[C{{r}_{2}}O_{7}^{2-}\]
D) \[Cr{{(OH)}_{2}}\]
Correct Answer: A
Solution :
\[\text{Cr}{{\text{O}}_{\text{3}}}\]dissolves in aqueous\[\text{NaOH}\]to give sodium chromate. \[Cr{{O}_{3}}+2NaOH\xrightarrow{{}}\underset{\text{sodium}\,\text{chromate}}{\mathop{N{{a}_{2}}CrO{{}_{4}}}}\,+{{H}_{2}}O\]You need to login to perform this action.
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