A) \[3.5\text{ }g\]
B) \[2.8g\]
C) \[5.4\text{ }g\]
D) None of these
Correct Answer: C
Solution :
From Faraday?s second law, if electric currents of same strength be allowed to flow in different electrolytes for the same time, then the masses of the substances liberated are directly proportional to their chemical equivalents. \[\therefore \] \[\frac{{{m}_{2}}}{{{m}_{1}}}=\frac{{{E}_{2}}}{{{E}_{1}}}\] \[\Rightarrow \] \[{{m}_{2}}=\frac{{{E}_{2}}}{{{E}_{1}}}.{{m}_{1}}\] Given, \[{{E}_{2}}=108,\,\,\,{{E}_{1}}=32,\,\,\,\,{{m}_{1}}=1.6g\] \[\therefore \]\[{{m}_{2}}=\frac{108}{32}\times 1.6=5.4g\]You need to login to perform this action.
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