A) \[31.4\text{ }Nm\]
B) \[3.14\text{ }Nm\]
C) \[0.314\text{ }Nm\]
D) zero
Correct Answer: D
Solution :
Torque \[(\tau )\] acting on a loop placed in a magnetic field B is given by \[\tau =nBIA\,\sin \theta \] where A is area of loop, I the current through it, n the number of turns, and \[\theta \] the angle which axis of loop makes with magnetic field B. Since, magnetic field of coil is parallel to the field applied, hence \[\theta ={{0}^{o}}\] and \[\sin \,\,{{0}^{o}}=0\] \[\therefore \] \[\tau =0\]You need to login to perform this action.
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