A) \[16\]
B) \[6\]
C) \[8\]
D) \[20\]
Correct Answer: A
Solution :
Given that \[n(N)=12,\,n(P)=16,\,n(H)=18,\] \[n(N\cup P\cup H)=30\] and \[n(N\cap P\cap H)=0\] Now, \[n(N\cup P\cup H)=n(N)+n(P)+n(H)\] \[-n(N\cup P)-n(P\cap H)-n(H\cap N)\] \[+n(N\cap P\cap H)\] \[\Rightarrow \] \[n(N\cap P)+N(P\cap H)+N(H\cap N)\] \[=n(N)+n(P)+n(H)-n(N\cup P\cup H)\] \[=(12+16+18)-30\] \[=46-30=16\]You need to login to perform this action.
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