A) First
B) Second
C) Third
D) Fourth
Correct Answer: C
Solution :
For an open pipe of length the frequency n is given by \[n=n'\frac{v}{2l}\] where v is velocity of sound, n' the overtone. Given, \[n=480\,Hz,\,\,l=1m,\] \[v=330\text{ }m/s\] \[n'=\frac{n(2)}{v}\] \[=\frac{480\times 2\times 1}{330}=2.9\approx 3\] Hence, this is the second overtone or third harmonic.You need to login to perform this action.
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