A) \[\frac{a-S}{S}\]
B) \[\frac{S-a}{S}\]
C) \[\frac{a}{1-S}\]
D) \[\frac{S-a}{a}\]
Correct Answer: B
Solution :
Sum of an infinite \[GP=\frac{a}{1-r}=S\] \[\Rightarrow \] \[a=S(1-r)\] \[\Rightarrow \] \[a-S=-Sr\] \[\Rightarrow \] \[r=\frac{S-a}{S}\]You need to login to perform this action.
You will be redirected in
3 sec