A) is ahead in phase by n
B) lags in phase by n
C) is ahead in phase by ?
D) lags in phase by ?
Correct Answer: D
Solution :
In a purely inductive circuit, current is \[i={{i}_{0}}\,\,\sin \,\left( \omega t-\frac{\pi }{2} \right)\] Which shows that the current lags behind the emf by a phase angle of \[\frac{\pi }{2}\] or \[{{90}^{o}}\] or the emf leads the current by a phase angle of \[\frac{\pi }{2}\] or \[{{90}^{o}}\]You need to login to perform this action.
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