A) Sc
B) Ti
C) Mn
D) Zn
Correct Answer: C
Solution :
Mn exhibits the maximum number of oxidation states. \[Mn(Z=25):[Ar]\,3{{d}^{5}},4{{s}^{2}}\] It can show \[+\,2,+\,3,+\,4,+\,5,+\,6\] and \[+\,7\]oxidation states.You need to login to perform this action.
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