A) 4
B) 3
C) 2
D) 1
Correct Answer: A
Solution :
\[[Co{{(N{{H}_{3}})}_{6}}]C{{l}_{3}}\]gives 4 mole of ions on complete ionization. \[[Co{{(N{{H}_{3}})}_{6}}]C{{l}_{3}}{{[Co{{(N{{H}_{3}})}_{6}}]}^{3+}}+3C{{l}^{-}}\]You need to login to perform this action.
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