J & K CET Engineering J and K - CET Engineering Solved Paper-2006

  • question_answer
    In the following reaction, X and Y respectively are \[{{C}_{2}}{{H}_{5}}OH\xrightarrow{KMn{{O}_{4}}/{{H}^{+}}}X\frac{Y}{{{H}_{2}}S{{O}_{4}}/\Delta }C{{H}_{3}}C{{O}_{2}}{{C}_{2}}{{H}_{5}}\]

    A)  \[C{{H}_{3}}OH,{{C}_{2}}{{H}_{5}}OH\]

    B) \[~C{{H}_{3}}CHO,C{{H}_{3}}OH\]

    C) \[~C{{H}_{3}}C{{O}_{2}}H,\text{ }{{C}_{2}}{{H}_{5}}OH\]

    D) \[~{{C}_{2}}{{H}_{4}},C{{H}_{3}}CO{{}_{2}}H\]

    Correct Answer: C

    Solution :

     \[\underset{\text{ethanol}}{\mathop{{{C}_{2}}{{H}_{5}}OH}}\,+[O]\xrightarrow{KMn{{O}_{4}}/{{H}^{+}}}\underset{\text{ethanoic}\,\text{acid}}{\mathop{\underset{(X)}{\mathop{C{{H}_{3}}COOH}}\,}}\,\] \[\underset{(esterification)}{\mathop{\xrightarrow[{{H}_{2}}S{{O}_{4}}/\Delta ]{{{C}_{2}}{{H}_{5}}OH(\gamma )}}}\,\underset{\text{ethyl}\,\,\text{ethanoate}}{\mathop{C{{H}_{3}}COO{{C}_{2}}{{H}_{5}}}}\,\] Hence, \[X=C{{H}_{3}}COOH\] \[Y={{C}_{2}}{{H}_{5}}OH\]


You need to login to perform this action.
You will be redirected in 3 sec spinner