A) \[1\]
B) \[2\]
C) \[-1\]
D) \[-2\]
Correct Answer: A
Solution :
\[\underset{x\to 1}{\mathop{\lim }}\,\frac{2{{x}^{2}}+x-3}{3{{x}^{3}}-3{{x}^{2}}+2x-2}\] \[=\underset{x\to 1}{\mathop{\lim }}\,\frac{(2x+3)\,(x-1)}{(3{{x}^{2}}+2)(x-1)}\] \[=\underset{x\to 1}{\mathop{\lim }}\,\frac{2x+3}{3{{x}^{2}}+2}=\frac{5}{5}=1\]You need to login to perform this action.
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