A) \[x+3y=0\]
B) \[3x+y=0\]
C) \[2x+3y=0\]
D) \[3x+2y=0\]
Correct Answer: B
Solution :
Limiting points of a coaxial system of circle are the points of the system of circle ie, circles of radii are zero. Given limiting points are \[(1,\,\,2),\,\,(-2,\,1)\]. \[\therefore \] Required equation of radical axis of the coaxial system of circle is \[3x+y=0.\]You need to login to perform this action.
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