A) \[{{0}^{o}}\]
B) \[{{30}^{o}}\]
C) \[{{45}^{o}}\]
D) \[{{90}^{o}}\]
Correct Answer: A
Solution :
Angle between the line and plane is \[\sin \theta =\frac{aa'+bb'+cc'}{\sqrt{{{a}^{2}}+{{b}^{2}}+{{c}^{2}}}\sqrt{a{{'}^{2}}+b{{'}^{2}}+c{{'}^{2}}}}\] \[=\frac{1\times 1+2\times -1+1\times 1}{\sqrt{1+4+1}\sqrt{1+1+1}}\] \[=\frac{1-2+1}{\sqrt{6}\,\sqrt{3}}=0=\sin \,{{0}^{o}}\] \[\Rightarrow \] \[\theta ={{0}^{o}}\]You need to login to perform this action.
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