A) \[4x-2y=11\]
B) \[5x-2y=10\]
C) \[5x-2z=11\]
D) \[5x+2z=11\]
Correct Answer: C
Solution :
Given \[A(3,1,2)\] be the foot of the perpendicular from \[B(-2,1,4)\] on the plane, then direction ratios of BA, the normal to the plane are \[(3+2,1-1,2-4)=(5,0,-2)\] Also, it passes through \[A(3,1,2),\] then equation of the plane is \[5(x-3)+0(y-1)-2(z-2)=0\] \[\Rightarrow \] \[5x-15+0-2z+4=0\] \[\Rightarrow \] \[5x-2z=11\]You need to login to perform this action.
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