A) \[{{A}^{-1}}\]
B) \[{{A}^{T}}\]
C) \[A\]
D) \[-A\] (Here, \[{{A}^{T}}\] is the transpose of A)
Correct Answer: A
Solution :
Given, \[A=\left[ \begin{matrix} a & b & 0 \\ -b & a & 0 \\ 0 & 0 & 1 \\ \end{matrix} \right]\] \[\Rightarrow \] \[|A|={{a}^{2}}+{{b}^{2}}=1\] \[\therefore \] \[{{A}^{-1}}=\frac{1}{|A|}adj\,(A)=adj\,(A)\]You need to login to perform this action.
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