A) \[\frac{1}{10}\]
B) \[\frac{1}{11}\]
C) \[\frac{1}{50}\]
D) \[\frac{2}{15}\]
Correct Answer: B
Solution :
The galvanometer G and shunt S is connected in parallel, hence potential difference is the same. \[\therefore \] \[{{i}_{g}}\times G=(i-{{i}_{g}})\times S\] \[\Rightarrow \] \[\frac{{{i}_{g}}}{i-{{i}_{g}}}=\frac{S}{G}=\frac{5}{50}=\frac{1}{10}\] \[\Rightarrow \] \[10{{i}_{g}}=i-{{i}_{g}}\] \[\Rightarrow \] \[11\,{{i}_{g}}=i\] \[\Rightarrow \] \[\frac{{{i}_{g}}}{i}=\frac{1}{11}\]You need to login to perform this action.
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