A) \[3\text{ }s\]
B) \[\text{4 }s\]
C) \[2.5\,\,s\]
D) \[120\,\,s\]
Correct Answer: A
Solution :
Torque is denned as rate of change of angular momentum \[\therefore \] \[\tau =\frac{dJ}{dt}=\frac{d\,(I\omega )}{dt}\] Given, \[\tau =40N-m,\,\,\,I=5kg-{{m}^{2}},\,\,\,\omega =24rad/s\] \[dt=\frac{d(I\omega )}{\tau }=\frac{5\times 24}{40}=3s\]You need to login to perform this action.
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